Recent content by eri1125

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    Equilibrium Points and Trajectories in the x-xdot Plane

    usually xdotdot is acceleration and xdot is velocity so xdot: dx/dt xdotdot : d2x/dt2
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    Solve Algebra Questions: Ladder Slips with Bob Climbing n Up | L,n,x,y,a

    thnx newayz i think ill just do it that way~~ thank you!~ what about an expression in terms of t, for the speed of the foot of the ladder when the top of the ladder is slipping at a constant rate of 4m/s? the ladder is still 5m and its height against the wall is 4m. i got v(x) = -4t...
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    Solve Algebra Questions: Ladder Slips with Bob Climbing n Up | L,n,x,y,a

    the equation must b expressed using x,y,n,L and the ladder slipping while bob moves n up or down must be taken into account i was thinking if his path could be modeled as a circle, and any other distance on the ladder becomes an ellipse model (if bob is at 3m on the ladder) maybe, we...
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    Solve Algebra Questions: Ladder Slips with Bob Climbing n Up | L,n,x,y,a

    nope, that's all they gave to work with a previous question talked about his path as a circle, but that's when bob was at 2.5m on the ladder.
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    Solve Algebra Questions: Ladder Slips with Bob Climbing n Up | L,n,x,y,a

    the general equation for Bob's position as a ladder slides down the wall, given that Bob climbs n up the ladder. the rate at which the ladder is stated isn't specified. just express the equation in terms on x, y, n & L what i have as working out is something i came up with which doesn't...
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    Solve Algebra Questions: Ladder Slips with Bob Climbing n Up | L,n,x,y,a

    Homework Statement a ladder (L meters) makes a right angled triangle against the wall, while the ladder slips, a person, Bob, climbs n up the ladder. So, the distance bob is climbing is n, and his distance from the top of the ladder is (L-n). The height of the ladder can be expressed as b+y...
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