Recent content by eric.mercer92

So: T1 = (W/σ4piR12)1/4 and: T2 = (W/σ4piR22)1/4 ?

I am really confused, can you clarify? The temperature of the outer shell isn't just T1 = (W/σ4piR^2)^(1/4) because it also absorbs more heat from the inner shell? So how do we find out how much heat the inner shell radiates? Doesn't that also depend on the heat of the outer shell?

I am sorry, I don't understand. Are you saying that all three objects absorb and radiate the heat from each other? So are you saying that they have the same temperature?

Homework Statement There is a perfectly absorbing spherical shell with radius R1 suspended in space. Inside is a smaller spherical shell with radius R2. Inside that shell is a ball of radius R3. All three objects are concentric. In the center of the ball is a point source radiation with power...

Ahh yes, I see, thank you very much. I got the same answer. Thanks again!

I thought about that, but it just didn't seem right, after all, if one of the y's is over 10/45, the other y's can be less than that to make up for it.

Homework Statement The probability density function of a random variable y is: f(y) = 100ye^{-10y}, if y>0 f(y) = 0 otherwise What is the probability that 45y <= 10? Homework Equations E(y) = ∫yf(y)dy Var(y) = ∫(y-E(y))f(y)dy The Attempt at a Solution I...