Recent content by Eric71

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    Bohr model and relativistic electron mass

    Thanks blue_leaf77. I think I understand now. I simply calculated the kinetic energy since v<<c. I forgot to add the potential energy, which is twice the kinetic energy but negative, hence the sign error in my result.
  2. E

    Bohr model and relativistic electron mass

    Thanks jfizzix But that's what surprises me so much. The energy difference due to this relativistic effect of "only" 3 in 100,000 (to be more precise 2.66 in 100,000) is the same as the energy level of the electron from the Bohr model: 2.66/100000 * mc2 = 13.5 eV
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    Bohr model and relativistic electron mass

    From Bohr's model of the Hydrogen atom in the ground state v = e2/(2εh) = 2.18x106 m/s Using m=m0 / √(1-v2/c2) and E=(m-m0)*c2 leads to E = 13.5 eV Using Bohr's equations E = m*e4/(8ε2h2) also gives 13.5 eV I tried to see what can be derived by substituting the first equation in the second...
  4. E

    Bohr model and relativistic electron mass

    From the semi-classical Bohr model of the hydrogen atom the velocity of the electron in a certain orbit can be determined. With these velocities the electron's relativistic masses can be determined. With E=mc2 the energy levels are in agreement with those from the Bohr model. I know Bohr's model...
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