So I'm performing the reaction using:
urea + diethyl n-butylmalonate ----NaOEt---> n-butylbarbituric acid
My question is, after adding everything, you mix it and heat it, what is the solid that separates during this reaction? I've been thinking it might be diethyl n-butylmalonate but...
cool, that helps. Basically, I've taken it that the reason why I got 92 percent S in this reaction of yeast alcohol dehydrogenase and acetoacetate is because NADH can only donate to the acetoacetate from one side that fits (the S). And the small amount of R would likely be from induced fit model...
Woops! I meant hydroxy. Hm, maybe I read this was under pressure. My lab book says 180-182 for the s enantiomer. I'm still confused as to why the re face of ethyl acetoacetate is so much more favorable in my reduction reaction using alcohol dehydrogenase. Any clue?
The boiling point for R-ethyl 3-hyrdoxybutanoate is about 75 C
The boiling point for S-ethyl 3-hyrdoxybutanoate is about 180 C
How!?
How is the same molecule that much more stable just by rearrangement of the hydroxy group. I'm trying to explain how some R enantiomer may boil off along with...
Okay so besides anhydrous diethyl ether, what other solvents could I use for a Grignard? What makes it a good solvent and what makes something a bad solvent? I know we want something that isn't miscible with water in the least bit because this would kill the reaction, but what else?
Thanks