Recent content by Erucibon
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Circular motion and g forces in rollercoaster
When i calculate the g force for this, is it equal to (a+g)/g at the bottom and (a-g)/g at the top, where a is the centripetal acceleration? Or is it just a/g (ac = a net ?)- Erucibon
- Post #8
- Forum: Introductory Physics Homework Help
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Circular motion and g forces in rollercoaster
At the top fnet=ma=Fc=N+mg=ma(centripetal) To not come off, N>= 0 mac - mg >= 0 ac>=g v^2/r >= g v >= root(rg) Using conservation of energy between top and bottom of loop v(bottom) = root(5rg) If this is correct, I'm not sure what to do next- Erucibon
- Post #6
- Forum: Introductory Physics Homework Help
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Circular motion and g forces in rollercoaster
I worked out a relationship here. I am not sure what you mean by the forces at the top and i think the top is where i messed up. Sorry I forgot to attach my working.- Erucibon
- Post #3
- Forum: Introductory Physics Homework Help
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Circular motion and g forces in rollercoaster
I my attempt, I set the drop height to 20m and using conservation of energy, i calculated the speed at the bottom. Calculating centripetal acceleration, if the radius of the circle is less than 10m then the g force is greater than 5, if equal to 10m the velocity at the top is 0 and there is 0...- Erucibon
- Thread
- Circular Circular motion Forces Motion Rollercoaster
- Replies: 15
- Forum: Introductory Physics Homework Help