When i calculate the g force for this, is it equal to (a+g)/g at the bottom and (a-g)/g at the top, where a is the centripetal acceleration? Or is it just a/g (ac = a net ?)
At the top fnet=ma=Fc=N+mg=ma(centripetal)
To not come off, N>= 0
mac - mg >= 0
ac>=g
v^2/r >= g
v >= root(rg)
Using conservation of energy between top and bottom of loop
v(bottom) = root(5rg)
If this is correct, I'm not sure what to do next
I worked out a relationship here. I am not sure what you mean by the forces at the top and i think the top is where i messed up. Sorry I forgot to attach my working.
I my attempt, I set the drop height to 20m and using conservation of energy, i calculated the speed at the bottom. Calculating centripetal acceleration, if the radius of the circle is less than 10m then the g force is greater than 5, if equal to 10m the velocity at the top is 0 and there is 0...