Recent content by Eruestan

that looks a lot more like the other formulas we've seen so assuming it is correct, thankyou very much!

also I've just seen some parts cancel so I'm left with v^2 = l^2/(τ^2 + l^2/c^2)

okay so v = l/τgamma = (l/τ)(1 - v^2/c^2)^1/2 so V^2 = (l/τ)^2 - (lv/τc)^2 so v^2 + (lv/τc)^2 = (l/τ)^2 so v^2(1 + (l/τc)^2) = (l/τ)^2 so v^2 = l^2/(τ^2(1 + (l/τc)^2) Is that correct?

Yes that was a very silly mistake! Ah so I have! I always get them the wrong way round, something I need to get right for definite. So now I have v^2 = l^2/τ^2(1-(l/τc)^2) Is that more like it? When I tried to do it a few other ways I see that my problem was always factorising the v...

oops that was a very silly mistake! So instead I should have got v = lgamma/τ so v=l/τ(1 - v^2/c^2)^1/2 so v^2 = l^2/τ^2(1 - v^2/c^2) but now I'm a little stuck. How do I factorise out v from this? Or have I used a wrong substitution?

so v=l/t and t=gamma/τ so v = lτ/gamma and gamma=(1-v^2/c^2)^-1/2 so v=lτ(1-v^2/c^2)^1/2 v^2=(lτ)^2 (1-v^2/c^2) I rearranged it to get v^2(1 +(lτ)^2/c^2) = (lτ)^2 So v^2= (lτ)^2 / (1 + (lτ)^2/c^2)) Is that correct?

so I tried gamma = (1- v^2/c^2)^-1/2) and rearranged to get v = c(1- 1/gamma^2)^1/2 and tried subbing in either gamma = τ/t so v = c(1 - t^2/τ^2)^1/2 but I didn't really know where to go from there

Homework Statement Λ particle has a proper life-time τ = 2×10−10 s. After being born in the cloud chamber (a device to track energetic particles) of physics laboratory it left there a a 300cm long trail. Find the speed of this particle in the laboratory frame. Homework Equations...