Recent content by eshelton

converted to degrees. 33.62. got it. Thanks for all your help, truly appreciated!

I'm getting .586876 But I'm fairly certain that it is not right.

what program are we using for this? I'm not very familiar with using spreadsheets in this sense. I did the guess and check method on the calculator though. If I'm not mistaken, the graphs cross over each other many times, creating many values that yield 495. How do I know which one is the...

this is killing me, I'm so close.

I can't figure it out. The calculator that I'm using is giving me a ton of different answers and the program I'm doing my homework on says they're all wrong.

ok, so then the equation would be... 950.5 = 105.105 cos(theta) + 735 sin(theta) ?

yes, the acceleration should be 3.66, correct?

okay. I did the calculations and I get: 735 sin(theta) + 105.105cos(theta) = 446.45 honestly, I'm not really sure how to get theta by itself

okay so... Friction = 105.105 cos(theta) and then i have to set the net force on the object equal to ma? Fg+Fparallel+N+Friction = ma ?

or would the F component of μ = F/N be (mass)(acceleration) of the hanging object?

would it be... μ = (mg sin(theta)) / (mg cos(theta)) ?

Ok. This graph is very helpful. First off, the angle opposite of Fparallel would be theta? assuming so... Fparallel = mg sin(theta) N = mg cos(theta) then, even though the equations have 2 undefined variables, I can write a formula for friction? Would I use μ = F /N ?

thanks for responding so quickly. from what i can understand, I've drawn three vectors, the vertical one with a value of mg, being opposite of theta. The other two vectors touch each end of the mg vector and form a triangle. Would these vectors have a designated value?? if so, is it given in...

Homework Statement A 75.0 kg mass sits on an inclined plane, and a rope passing over a pulley at the top connects it to a hanging 125 kg mass. The pulley is frictionless and its mass is negligible. The coefficient of friction between the 75.0 kg block and the plane is 0.143. The system is...