Recent content by Estartha

Okay, I think I see it now. If we're using the isospin representation, then we have to regard the proton and neutron as indistinguishable fermions which means the deuteron's wave function is antisymmetric. Thank you for your help!

So I'm guessing isospin assumes that we're looking at two states of one particle, so we're assuming that the proton and neutron are "states" of a particle we're calling the nucleon, so the idea is that we regard the proton and neutron as identical fermions? And identical fermions (say particles...

Homework Statement The deuteron is mostly a bound state of a proton and neutron with orbital angular momentum L=0 and spin S=1. To a good approximation we can neglect the proton-neutron mass difference and electromagnetic interactions, and treat the proton and neutron as two isospin components...