Oh! Okay then, that is what I needed to hear. Up until now, I had approached this problem much like this visually:
[+++++] <- Capacitor plate
- <- say a negative charge in the center between the plates
[------] <- Capacitor plate
In this simple view, the charge farthest...
Ah, I see. Well perhaps I'm just confused over the meaning of the electric field between two capacitor plates. Even if the plates are considered infinite in area...well what is wrong with this understanding of the constant electric field:
Let's say you have two plates (XXXXX) spread apart...
I'm still not quite seeing all there is to see here. Let's isolate the condition in which the plates are not connected to a battery. If C = Q/V is true, than in order for capacitance to follow these laws we discuss, the potential difference must be doubled when distance is doubled. This would...
On a side note, the effects of gravity would lead to a particle overall being more likely to be found near the bottom of a standing container. Aside from that, I have not enough experience with physics probability to comment further.
Hrmm, I see. I believe I am confused of the definition of electric potential difference in this situation. Initially, I just think of it as the amount of charge on a plate divided by distance between the plates. Hmm...
So potential difference doubles when distance is doubled..what exactly...
Well I understand the argument that the area of a capacitor plate does not influence electric field significantly. However, when it comes to distance, I just don't see where the argument is coming from. Two plates separated an infinite amount would have a potential difference of 0, considering...
Physics Question:
All right, well I have read over the textbook-type material behind the questions I am about to ask. So, I really don’t want equations thrown at me. My problem is mostly with conceptual-level information:
A) Concerning Capacitance- If you had two capacitor plates that were...