AAAH. Fixed that and plugged in again.
YES I got 1.27E-13 for the magnitude of the plates. WHICH IS THE CORRECT ANSWER :D. OMG. It only took 4 hours xD.
I just wanted to thank you for being tenacious enough to stick with the help to the end. I'm so slow with new concepts ><. Thanks alot, I...
I just did this and got 1.15x10^-13 - I know the correct answer is 1.13x10^-13 O_O
*edit* Meant to quote what you just Quoted, I have no idea why it quoted this.
I got 6.6339E-22 for U, .004146 for E and 5.36811E-12.
I know it's asking for the charge on each plate - but I have no idea how to find that since I've never had a problem like this. I was planning on finding E then plugging it into E=(Kq1)/(r1)^2 and use the midpoint between the two plates as...
Ok corrected; that got my Ue to 6.55452E18 - which when plugged into my V got me 4.09658E37. That lead to Q being 1.00243E37 and E being some huge number =\.
KEo= (1/2)(9.10938188 × 10-31)(1.63x10^4)
KEf= (1/2)(9.10938188 × 10-31)(4.15x10^4)
KEf-KEo=Delta KE which is where I got 1.148E-26
I assumed the change in kinetic energy would be equal to the change in potential energy. So I took the magnitude of it and plugged in all the way through -...
If I calculated it correctly I got 1.147x10^-26 - plugged that in for delta Ue; plugged Ue into the V equation - plugged V into the Q equation - which I plugged in for E and I got the wrong answer =s.
Unless I'm missing something (which I problem am due to my own ignorance ;_;) I still have multiple unknowns.
UGH, it's irritating having an assignment which seems easy until you get to the last problem.
Any other clues you can prompt me to? =\