Can you explain how to link them?
Otherwise,
E1 = 1/2mv2, which is just 25 J, since only 1 ball is moving.
Do i not know E2 as well since i have their masses and their final velocities? where does momentum come in? I know it is not this simple.
Homework Statement
A 500 g billiard ball is going at 10 m/s [E] when it impacts 2 other identical billiard balls. Afterwards, you observe 2 of the balls moving at 2 m/s [30 W of S] and 3 m/s[45 N of E] respectively. Calculate the Energy lost in the collision.
Homework Equations
KE = 1/2mv^2...
Found out how to get A and φ, but now i would need v0 , more relevant equations i guess:
v=Aw cos(wt+Ø)
a=Aw² sin(wt+Ø)
A = (y)^2 +(v/w)^2
Ø = tan-1 (y*w/v)
max for sine is 1, min is -1, amplitude is 1.
units of y are m or i was thinking of doing them in cm, the mass will go upwards when it is released, to i don't know how to calculate the max height.
When released at time 0, it will be "pushed" upwards since it will be trying to restore to its...
Amplitude is half the distance between the max and min, but since it is damped, the max and min will both be "shrinking" with time. Are location units like coordinates? so wouldn't i plug in values?, but the problem is how do i find max/min without amplitude, or do i just find amplitude and then...
from wiki, makes sense now since its a sinusoidal graph the units should be radians per second
finally figured it out now: angular frequency: ω = 35.36, period: 0.178s, ordinary frequency: 5.628 Hz
at time 0, it is at equilibrium so -.028m, sin(0) is 0 and since it completes 1 cycle in 0.178s...
Scratch the equation, doesn't look right at all with the (1/2)^t, looks like simple harmonic without it, so now the problem i think is how to incorporate the losing 50% energy every second so that it becomes damped harmonic motion?
Right my bad on the units part, so 125 N/m
The spring will sag: From F = -kx,
0.1*-9.8 = -125*Δx
Δx = 0.00784, it will sag 0.784 cm
35.36 is the period which is measured in seconds
Also my bad, it should be y = something in terms of t, y being distance and t being time
I think it should be at...
Homework Statement
When a 100 cm long thing aluminium rod is lodged into the ground, so that it is vertical, it requires 25.0 N of force to deflect it 20.0 cm from the rest position. The rod is then lodged into the side of a wall, and a 100 g of mass is placed at its end and it is then pulled...
Alright cool, but unfortunately i got a negative answer when i did Mars subtract Earth.
For Earth i got: - G*(Mass of rocket)*(Mass earth)/ radius of Earth - G*(Mass of rocket)*(Mass of Sun)/ distance between sun and Earth + 1/2*(mass of earth)*(2pi*distance between Earth and sun)^2 + 1/2*(mass...
No we're not suppose to take into account fuel. My other friend said something like this: Total energy on Mars - Total energy on Earth = energy required
And Total energy on Earth consists of: PE - Earth on rocket, PE of sun on rocket, KE of Earth's rotation, KE of rocket traveling around the sun...
Got a better understanding now, apparently there is a point at which Fg Earth + Fg sun = Fg mars, the sun is needed since its a massive body and its gravitatio0nal field will have a effect on you. Anyways, we need to find the energy needed to get to that point so that Mar's gravity will be...