awkward, that is it!
That gives a value of 53.5802554, which is right in the range that my simulation suggests!
Thank you so much for the formula and the explanation!
Excellent!
It sounds like Stirling numbers of the second kind are definitely related to what I need.
(By the way, I love this line from the Wikipedia article: "Stirling numbers of the second kind is one of two types of Stirling numbers, the other type being called Stirling numbers of the...
Hello!
I need your help. I’m really terrible at statistics, probability, permutations, and combinations. I’ve looked around a lot for the answer to this, but I haven’t seen anything just like it. I need the answer to this for some research that I’m doing.
Here’s the situation:
Imagine 60...