I tried to clarify this earlier...
Decimal seconds are allowed. The seconds do not have to be integers. But give your answers with fractions.
Unfortunately, this is a brain teaser and not a practical problem. So, 'close enough' is not equidistant.
This time is: 4:00:40. This is not a valid solution:
From minute to hour: 119 2/3°
From hour to second: 119 2/3°
From second to minute: 120 2/3°
The hour hand cannot be at 4:00 or the minute hand at 12:00 when the second hand is at 8:00, because it would now be 40 seconds after 4:00, thus the...
Parlyne is correct. I wanted to exclude 12:00:00 from consideration as an answer, because all three hands are on top of each other. But one hand can be pointing at 12.
8:20:00 is not a valid solution:
From second to minute: 120°
From minute to hour: 130°
From hour to second: 110°
Shollenbarger's Clock:
Excluding 12:00, Is there ever a time on a clock where the second, minute and hour hands are equidistant from each other? (In other words, the three hands are all 120° apart? If yes, give the EXACT time(s) that this occurs. If no, prove that no such time exists. Good Luck!