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Graduate Shollenbarger's Clock: Proving No Time Exists Where Hands Equidistant
I tried to clarify this earlier... Decimal seconds are allowed. The seconds do not have to be integers. But give your answers with fractions. Unfortunately, this is a brain teaser and not a practical problem. So, 'close enough' is not equidistant.- expectedvalue
- Post #17
- Forum: General Math
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Graduate Shollenbarger's Clock: Proving No Time Exists Where Hands Equidistant
No, unfortunately 3:59:39 is not a valid answer: From minute to hour: 121.925° From hour to second: 114.175° From second to minute: 123.9°- expectedvalue
- Post #8
- Forum: General Math
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Graduate Shollenbarger's Clock: Proving No Time Exists Where Hands Equidistant
This time is: 4:00:40. This is not a valid solution: From minute to hour: 119 2/3° From hour to second: 119 2/3° From second to minute: 120 2/3° The hour hand cannot be at 4:00 or the minute hand at 12:00 when the second hand is at 8:00, because it would now be 40 seconds after 4:00, thus the...- expectedvalue
- Post #6
- Forum: General Math
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Graduate Shollenbarger's Clock: Proving No Time Exists Where Hands Equidistant
Parlyne is correct. I wanted to exclude 12:00:00 from consideration as an answer, because all three hands are on top of each other. But one hand can be pointing at 12. 8:20:00 is not a valid solution: From second to minute: 120° From minute to hour: 130° From hour to second: 110°- expectedvalue
- Post #4
- Forum: General Math
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Graduate Shollenbarger's Clock: Proving No Time Exists Where Hands Equidistant
Shollenbarger's Clock: Excluding 12:00, Is there ever a time on a clock where the second, minute and hour hands are equidistant from each other? (In other words, the three hands are all 120° apart? If yes, give the EXACT time(s) that this occurs. If no, prove that no such time exists. Good Luck!- expectedvalue
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- Clock
- Replies: 27
- Forum: General Math