Recent content by Eyesaw

Your starting assumption is that there is a line segment with finite points on it. Then you introduce an assumption (high school geometry of constructing the midpoint between any two points) that contradicts your starting assumption to prove your starting assumption is contradictory. That is...

Moving finger, it's still unclear to me how you are concluding there can be free will in a purely deterministic universe, though I agree with you that the UP doesn't help explain it. If the choices I make every day are a result of deterministic forces- for example, I decided to go to the...

I agree with what you are saying and my previous posts weren't a direct response to your posts really though I really don't see how probability is very useful for describing a coin toss.For like a 6 sided dice that have 5 numbers the same for example it would be useful. I was reducing the...

A coin flip and a knife flip are the same mathematically. Both have two possible outcomes. I used the knife flip as example because it is easier to control the flip of a knife than the flip of a coin. The point was that a person can determine with 100% probability each and every knife flip and...

Anyone who has watched those Asians juggling knives on TV would disagree with your assumption of independence and the correctness of the 50/50 model for coin tosses.

If we knew all the forces involved in the coin flip, shouldn't the probability of it landing heads or tails more like 100%? I thought the 50/50 figure is symbolic of the incomplete information we have for predetermining an outcome with two possible results and not a real figure? However, if we...

1. Wave motion is the composite motion of particles, thus for em waves to exist, a particle medium is required to carry them. The Ether was proposed as such a medium. Why the Ether if so many atoms are available to carry em wave motion? Probably to explain the odd fact that when they created a...

Yes, you showed that the second firing did 3 times more work, but did you show why 3 times more work didn't add 3 times more velocity to the pellet? No, the only answer you could give was that because K.E. is defined to be 1/2mv^2. If K.E. was undefined and you started from rest and applied a...

Well, the way you added up the total kinetic energy in your earlier post was 1/2mv^2 + mv^2 + 1/2mv^2 to get 2mv^2. Since you were viewing from the ground frame, in your example the second explosion actually released 3.0mv^2 of kinetic energy, judging by the final velocity of the left brick of...

The argument made here basically is that measured inside the inertial frame of the second firing, there's a quantity of kinetic energy c, which when viewed by an inertial frame moving at -v, obtains the value c-v. But after taking into account of the -v, the second inertial frame also obtains...

You left out the part in his post where he states that he knew how the formulas work out. "I guess what I'm pointing out is that squaring the velocity doesn't make much sense. I do understand how the formulas are derived, just not comfortable with the results" . By his third post, he left no...

I never doubted for a minute the definition of kinetic energy was consistent within Newtonian mechanics. I don't think slinkie did either. He made it clear by the second post that he knew how the math worked and was curious as to why velocity should be squared in kinetic energy. So I think I'm...

Sorry, misread again. How did krab get the 2v in the latter part of the derivation: (1/2)M\Delta(v^2)=(1/2)M(v_2-v)(v_2+v)=(1/2)M\Delta v(2v)=-mv^2 looks like he substituted (v_2+v) for 2v ?

I probably read more into Slinkie's gedunken than you guys did because if slinkie was just asking where the "extra" energy came from, the answer would have been trivial- the switching of inertial frames to calculate the kinetic energy of the pellet. Or more precisely, the "extra" energy is a...

Actually, if slinkie was interested in the conservation of momentum, a collison would've served as a better example. I think what you have said above is that if K.E. is defined to be 1/2mv^2 then the pellet will have 2mv^2 k.e. after the second firing, that it got this 1.5mv^2 more energy from...