Recent content by fab672000

I really do find iterative not as satisfying (thought it is working well now so that at least i have one acceptable solution), but when i entered the system in 2 different linear equations solvers, they found no solution of the upper so I thought that an augmented matrix with a gauss jordan...

I found an iterative algorithm that first compute a candidate point O such as 2 vertices of the triangle are exactly 120 degree, it is not the final O point but will permit to converge to it: Then I converge so that the 3rd vertice is also at 120 deg +- 0.001 deg. by compensating it by...

So I tried with the angles and I indeed get 6 equations (for angles a=BAC, b=CBA, c=ACB, of main triangle each divided in two sub angles such as a=a1+a2,b=b1+b2, c=c1+c2) It give a system of linear equations of the form (after simplification of angle O = 120, so 180-O =60) : a1 + a2...

So as I understand what you would suggest: Let A,B,C be the 3 points of the main triangle. Let a,b,c be the length of segments BC,AC,AB. Let O be the center point we are looking for such as angles OAB=OAC=OBC=120deg. Let d, e, f be the lengths of OA,OB,OC As cos(O)=-1/2 per definition whatever...

Hi, I would like to understand how I can calculate the inner circle center of any equilateral triangle that has for constraint that each of its bissectors must intersect one extremity of the (for now let's assume bigger only) main triangle. For helping understanding my problem and approach...