I started working on some homework loosely based on circuit analysis and ran into a problem with lightning and trees and stuff. The question deals with lightning striking a tree and then "jumping" from the tree to a person standing nearby. It is a given that the person's resistance is...
For 1) It's induction. The 4 nC charge pulls a minus 4 nC charge towards itself from the conductor. 2) Is Gauss' law, and there really isn't another way to explain it.
I completely messed that up, then fixed it.
kg*m3/s2C2 are the terms for ke
You are correct. The answer to part two is wrong. As well as the others. You may want to recheck your work, TypeFun. I'm going to look over it myself and see what I can come up with.
The units for ke should be kg*m/s2C2
ke times a C2 (incorrect, fixed below) yields a Newton.
AH Correction: kg*m3/s2C2
forgot that there is a 1/r2 term in the equation for electrostatic force.
ke * C2/m2 yields a Newton.
Without doing any of my own work, here are a few pointers:
Be sure to account the fact that the given velocity is in km/h and not m/s.
Remember that the work done by a constant force can be written as F*x where x is the distance along which the force did the work.
Now, to account for the time...
Your time in flight equation seems to be derived only for when dY=0, so I believe you cannot use it. I would use V2=V02+2ay. V is the final velocity, V0 is the initial velocity, a is acceleration and y is change in height. Remember to use only velocities in the y-direction. This also works...
Well I've never seen that before in my life... if it was given in class I'd go with it. Lambda denotes charge per unit length, by the way jared. Charger per unit area is sigma and charge per unit volume is rho. I think O.O
I'm assuming this all has to do with electricity, correct? Lambda in electricity isn't mm3...double check your notes or Google possibly? Let me know if you can't get it.
Sorry for the double post, but I realized that I was being stupid. I guess it happens to all of us, no?
In a series of caps, Q is the same on all the caps in the series and is equal to the Q on the equivalent cap. Thanks for the help and the useful equations!
I knew the whole bit about serial caps having the same charge, and I've seen this equation before but didn't know where it came from nor how to derive it. Thanks for the tip! I'll see what I can come up with using what you gave me here.