so the other one will be
(a+b)^6 =(a^2 +b^2)^3- 3a^2b - 3ab^2
rite?..
i tried to solve and factorize the first one but can`t
it becomes 2(sin^2(x))^2 - sin^2(x) + 1 ??
guys , following is the problem
(sinx)^4 + (cosx)^4
and
(sinx)^6 + (cosx)^6
they are asking for the range for each of them
i really have know clue how to solve this...any sugeestion please?...thanks for reading this!
yes...typo sorry...1/2 * M/2* (V/2)^2 +1/2 * M/2* (3V/2)^2 =10/16*MV^2
right?...and thank you very much again tiny-tim for helping...
what abt next question...what concept or how should i continue?
hmmmmm... because my understanding was the speed of the fuel and the rocket must be the same becuase the mass is the same ...according to Newton`s 3rd law...
but after using that formulae...my new answer is 1/2 * M/2* (V/2)^2 +1/2 * M* (3V/2)^2 = 19/16*MV^2 ? is it correct?
i use the given V as the velocity relative to rocket to substituted into u in the formulae
i just want to quote the how the formulae i use looks like...
oooo...i sum up the kinetic energy of the rocket and fuel gas after the increase of the velocity...1/2 * M* (3V/2)^2 then multiplied by 2...
thank you very much for your advice...I use the mass given ..i just want to show the formulae i use =)...
mv = − dm (−u +v + dv ) + (m + dm )(v + dv )
i got this from some website
m- mass
v- velocity of rocket relative to observer
u- velocity of fuel relative to the rocket...
hmmm...
is the formulae correct by the way?...
i tried substituting again after relising that dm must be negative...
and i got the answer for 1.1 = 3/2M
is it correct?
for 1.2) should sum of the kinetic energy equal to 2(1/2)(M/2)(3V/2)^2 ?
i stucked at the first question...= =...so i didnt
this is what i thought of using this formulae
mv = − dm (−u +v + dv ) + (m + dm )(v + dv )
but when i substitutued all the variable into the formulae
MV = -M/2(dV) + M/2(V+dV)
but the dV i want to know is gone after sovling...
a problem regarding momentum(from an entrance exam to Uni in Japan)(editted)
Homework Statement
Homework Equations
In the space ,A rocket with mass M moving with constant velocity of V with no external force acting on it.
1) after sometime, the rocket release the fuel mass...