Recent content by farukh

:) now i think its ok

ok i just figured it out how to do the solutions with integration v(t) = integral 6t v(t) = 3t^2 + c 9 = 3(0)^2 + c 9 = c v(t) = 3t^2 + 9 but is there any way to do this without using integration because we haven't learned integration yet..

ok basicaly my question is does a(t) = a ? becuase the equation is v(t) = -at + v0 and if a(t)=6t then is this right v(t) = -6tt + v0

1. Given acceleration of an object is given by a(t) = 6t and the intial velocity is 9 m/s 2. the general form we learned is v(t) = -at + v0 3. so i guess v(t) = -6t^2 + 9 is that right ? can i substitute 6t for a ... or a(t) doesn't equal a