The integral of force with respect to time is not the work done by a force; it is the impulse of that force. The easiest way to convince yourself that there is a problem with your equations is by dimensional analysis. In your final equation, you have 2.8 kg * 16 m/s or 44.8 N*s. A Joule is a...
Pressure is force per unit area. However, I incorrectly stated above that pressure is directly proportional to the magnetic field. It is related, but not by direct proportionality. You should be able to see the relation in the equation that I included.
Now that you know the relation between...
Pressure, force per unit area, is most likely necessary to solve the problem. You know that you can assume that the area of the object does not change. Thus, the force that you are given is directly proportional to the magnetic field, which is directly proportional to the current and number of...
This is partially true. A magnetic field is a potential. When something is put into a magnetic field, some effect, such as attraction or repulsion, will be experienced by the object.
Also, magnetic field is directly proportional to current and directly proportional to number of loops for a...
Alright, first, the equation that you listed as a relevant equation is used to calculate the force on a current carrying wire by a given magnetic field. I do not think that that is what the question is looking for.
So, you and I will work through a step-by-step solution together.
The first...
I am concerned with the relevant equation. You do have an equation that includes I, but that does not mean that you are using the equation correctly.
Do you know which object the force that is calculated by the Lorentz Force (the equation that you used) acts on?
I would look at the equations...
The decay constant crops up in exponential decay problems in all sorts of different equations.
It is in the defining equation of exponential decay \frac{dN}{dt}=\lambda N. The solution to this equation is often written N=N_0 e^{\lambda t}.
You may see it most often in its inverse form as...
The activity is related to the half-life. Activity (A) = \lambda N. \lambda is the decay constant of the element and N is the number of atoms in the sample. Half-life (H) = ln(2)/\lambda. With this, you should be able to rewrite activity in terms of given quantities.