Got it
Thanks, I figured this out late last night right before i went to bed.
I forgot that <fx,fy,fz> were already in the form of the frictional vector and that the equation .231Fx + .923Fy + .308Fz was just meant to relate the components, they are not the actual components.
Thanks!
1350kg car resting on a plane surface with its brakes locked.
Unit vector e_n = <.231,.923,.308> is perpendicular to the surface. The y-axis points upwards. The direction cosines of a cable supporting the car are <-.816,.408,-.408> and the tension in the cable is 1.2KN. Determine the...