Recent content by fibonacci101
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Proving \int\int_{S} n dS = 0 for Closed Surface S
Okay! This is my last try and I hope I will be right .. Given a closed Surface S, the vector Area of this is zero. so that is i.t.- fibonacci101
- Post #26
- Forum: Calculus and Beyond Homework Help
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Proving \int\int_{S} n dS = 0 for Closed Surface S
So, How is it to be equal to zero? i don't know what to do. I thought I've already got the right solution. but it is quite wrong...- fibonacci101
- Post #24
- Forum: Calculus and Beyond Homework Help
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Proving \int\int_{S} n dS = 0 for Closed Surface S
div F = \left[\frac{\partial}{x}\vector{i} + \frac{\partial}{y}\vector{j}+\frac{\partial}{z}\vector{k}\right]\left(\vector{ni} + \vector {nj} +\vector{nk}\right) = 0 right?- fibonacci101
- Post #22
- Forum: Calculus and Beyond Homework Help
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Proving \int\int_{S} n dS = 0 for Closed Surface S
By the definition of divergence...see??- fibonacci101
- Post #20
- Forum: Calculus and Beyond Homework Help
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Proving \int\int_{S} n dS = 0 for Closed Surface S
Is this for me?- fibonacci101
- Post #19
- Forum: Calculus and Beyond Homework Help
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Proving \int\int_{S} n dS = 0 for Closed Surface S
Yeah.. That is 0... Thanks for helping and guiding me,Sir. Hope to guide me in my further studies.. Thanks again... I LOVE YOU! LOL- fibonacci101
- Post #17
- Forum: Calculus and Beyond Homework Help
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Proving \int\int_{S} n dS = 0 for Closed Surface S
div F = \left[\frac{\partial}{x}\vector{i} + \frac{\partial}{y}\vector{j}+\frac{\partial}{z}\vector{k}\right]\left(\vector{i} + \vector {j} +\vector{k}\right) div F =\left[\frac{\partial}{x}\vector{0} + \frac{\partial}{y}\vector{0}+\frac{\partial}{z}\vector{0}\right] div F = 0 + 0 + 0...- fibonacci101
- Post #15
- Forum: Calculus and Beyond Homework Help
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Proving \int\int_{S} n dS = 0 for Closed Surface S
Divergence Theorem said that \int\int_{S} \vec{F} \cdot \vec{n} dS = \int\int\int_{V} \nabla \cdot \vec{F} dV- fibonacci101
- Post #13
- Forum: Calculus and Beyond Homework Help
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Why Does the Integral Over a Closed Surface Equal Zero?
how do you prove this? Prove that \int\int_{S} n dS = 0 for any closed surface [SIZE="3"]S.- fibonacci101
- Post #8
- Forum: Introductory Physics Homework Help
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Proving \int\int_{S} n dS = 0 for Closed Surface S
\vec{n}=(\vec{i}\cdot\vec{n})\vec{i}+(\vec{j}\cdot \vec{n})\vec{j}+(\vec{k}\cdot\vec{n})\vec{k} Then, \int\int_{S}\vec{n}dS=\int\int_{S}(\vec{i}\cdot\vec{n})dS\vec{i}+\int\int_{S}(\vec{j}\cdot\vec{n})dS\vec{j}+\int\int _{S}(\vec{k}\cdot\vec{n})dS\vec{k} I stacked to this step...- fibonacci101
- Post #11
- Forum: Calculus and Beyond Homework Help
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Proving \int\int_{S} n dS = 0 for Closed Surface S
I will conclude that \int\int_{S} F \cdot n dS = 0- fibonacci101
- Post #9
- Forum: Calculus and Beyond Homework Help
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Proving \int\int_{S} n dS = 0 for Closed Surface S
Yeah, I get what you are saying... So If I choose an F a vector the solution will lead to Divergence Theorem? Am I right?- fibonacci101
- Post #7
- Forum: Calculus and Beyond Homework Help
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Proving \int\int_{S} n dS = 0 for Closed Surface S
Is there a value of n(outward unit vector)?- fibonacci101
- Post #5
- Forum: Calculus and Beyond Homework Help
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Proving \int\int_{S} n dS = 0 for Closed Surface S
my problem is how do I show that the \int\int_{S} n dS = 0 for any closed surface [SIZE="3"]S ----> I used the divergence theorem, but I don't think it will help me 'cause it is applicable for \int\int_{S} F{ \cdot} n dS not for \int\int_{S} n dS- fibonacci101
- Post #3
- Forum: Calculus and Beyond Homework Help
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Proving \int\int_{S} n dS = 0 for Closed Surface S
Homework Statement Prove that \int\int_{S} n dS = 0 for any closed surface [SIZE="3"]S.Homework Equations The Attempt at a Solution I used divergence theorem. But i thought it is applicable only if there is another vector multiplied to that outward unit vector (n). \int\int_{S} F {\cdot} n dS- fibonacci101
- Thread
- Integrals Surface Surface integrals
- Replies: 26
- Forum: Calculus and Beyond Homework Help