Recent content by fikus

you should write how horizontal and vertical distances depend on t, then express t from one equation (horizontal makes it easier), and put it in other.

from Maxwell equations and Ohm's law you can derive that conducting materials have complex index of refraction. The solution for propagating wave (exp(i*omega*x/c, where c is c_0/n) then gets a damping factor from the complex part of n. So you can easily find that depth. Complex part of n...

forget about that line integral, you need the surface one. From figure it should be clear why differential surface area (rectangle in figure) is as I wrote in one of previous posts.

that your flux is called electric current :) glad we cleard that.

your path integral is zero, since differential path element is perpendicular to magnetic field, of course, because there is no electric current through the loop, as states Ampere law. Your path integral gives total current through the loop which is zero of course. You don't get it right.

the field is not perpedicular to the normal of the surface! they have both the same direction. You should see that.

I disagree with you gabbagabbahey also. He is looking for flux as naresh said.

you don't really need any vectors, since area withing the loop and field are perpedicular. Differential area da is: dA = \sqrt{a^2+(\rho-b)^2} d\rho Maybe I should sketch this, but I hope you understand that.

you should use integration by parts to integrate V_{n+1}f(t) = \int_a^t \frac{(t-s)^n}{n!} f(s) \mbox{d}s try with \frac{(t-s)^n}{n!} = u , f(s)= dv It works for me.

The loop doesn't go around the wire, it has center moved for distance b from origin. Look at his sketch in attached pdf. Rho represents what you said, but the loop is not on constant rho, neither rho is the radius of the loop (which is a).

I think you're wrong, look at the picture in KleZMeR pdf. With rho I mean the distance from wire on z-axis, so rho is not constant through loop, if I understand the problem right.

Field B depends on rho as you wrote. Flux is: \int_{0}^{A} B \cdot dA Since you know field B as the function of rho, you should also express differential area dA in terms of rho (and d(rho)), so you'll get dA = f(rho)d(rho). Then you integrate \int_{a-b}^{a+b} B(\rho)f(\rho)d\rho ...

you have three equations, (1) and two equations in (2). Q_1/A_1 = Q_2/A_2 and Q_2/A_2 = Q_3/A_3.

uhh sorry, just look what determinant of transpose matrix is as cristo said.

try to look what is A^T A then use the rule for determinant of product.