Recent content by Fireant

thank you for the thorough explanation. it's true- i don't think of the equations symbolicaly enough and often become restricted in trying to figure out the numbers. i just need a better understanding of the problems...really see what I'm trying to calculate. one thing I'm having trouble...

thank u tiny tim! where's my prize?...just kidding...:[

Alright so it must be that tanθ=32.34/98 θ= 18.26° or 18°

...oh wow...lol..forgot about that. so 32.34costheta=sintheta-98 tantheta=130.34 theta=89.6 or 90 that seems wrong..

or would it be easier if: costheta=(sintheta-98)/32.34

lol I'm hopeless...! thank you so much for bearing with me ok going to try this out... 32.34costheta=sintheta-98 sintheta=32.34costheta+98 sintheta/32.34=costheta+98 Sorry, what am i dividing by and how?

im not sure how i would isolate theta...

0=32.34costheta-sintheta-98

but I'm missing sintheta right?

would be... Fnet=Fn-Ff-Fg 0=32.34cosθ-98 ?

so Ff=μsFN =0.33(mgcosθ) =0.33(98)(cosθ) =32.34cosθ

Sorry I'm at work, that's why it's taking so long to reply. the normal component of W would be mgcostheta?

I think I'm getting confused when you say 'the components in the normal direction'... do you mean on the y axis? Isn't that just FN? Which would be -98N ?

No I really appreciate your help... getting my noggin working... Fsmax=musN =mus(mg)(costheta) 0=mgsinθ-mμs(mg)cosθ that's the part where I'm confused... how do i isolate theta?

Hi thank you for responding! The mass of the box is 10kg. So the normal force here would have to be mg...? normal force=98N Ff=μs(FN) =0.33(98) =32.34 N and then tanθ= 97.5/98 θ=44° I got 97.5 (for the x component) from pythagorean theory... I'm pretty lost!