\theta(t) would be \omegat
You are right, the theta equation is wrong,
For theta, mgr\dot{\theta}cos\theta-2mr^2\ddot{\theta}+2mr\dot{r}\dot{\theta}=0, which can be simplified to gr\omega cos(\omega t)+2r\dot{r}\alpha=0
For r, r\omega^2+gsin(\omega t)=0
Is it possible to further simplify...