Recent content by fishking2

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    Circular Motion using polar coordinates - Mechanics

    Wow, I don't know how i missed that! Thanks! (d/dt)(f(g(t)) = f'(g(x))*g'(x) (d/dt)(f(g(t)) = -2(S-c1t2)-3*(-2c1t) So α= S2w0 * d/dt[ 1 / (S-c1t2)2 ] α= (-2S2w0 * (-2c1t)) / (S-c1t2)3 α=4S2w0c1t/ (S-c1t2)3You've been really helpful! Thanks!
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    Circular Motion using polar coordinates - Mechanics

    Haha, yes. I am confused at what point the dr/dt is entering into the equation. If I had to guess, it comes from the 'r' term that we plugged in. (S-c1t) However, since this is only in terms of 't' and the other values are all constants, I didn't think chain rule would apply. Would you...
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    Circular Motion using polar coordinates - Mechanics

    Angular momentum is conserved. L0=Lt L0=r x p = rm(rw) L0=S2m*w0 Lt= (S-c1t2)(m)(V) Vθ = r*dθ/dt Vθ = (S-c1t2)(w) S2m*w0=(S-c1t2)(m)((S-c1t2)(w)) S2w0=(S-c1t2)((S-c1t2)(w)) w = S2w0 / (S-c1t2)2α=dw/dt α= S2w0 * d/dt[ 1 / (S-c1t2)2 ] α= -2*S2w0 / (S-c1t2)3 This would be the answer if it were...
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    Circular Motion using polar coordinates - Mechanics

    No, it isn't a constant. However, if I am understanding the problem, α is what I am trying to solve for. And if that is correct, I am confused as to what I can set the components of force equal to, so that I can solve for alpha. I also believe I had a mistake in my Fθ component. Where I...
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    Circular Motion using polar coordinates - Mechanics

    I only listed the torques because it was part of the question. I don't think they are of any real significance. I guess that is wrong. Would I plug in (w0 + αt) instead?
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    Circular Motion using polar coordinates - Mechanics

    Homework Statement A block of mass M is on a frictionless table that has a hole a distance S from the block. The block is attached to a massless string that goes through the hole. A force F is applied to the string and the block is given an angular velocity w0 , with the hole as the origin, so...
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