Recent content by fixedglare

To get the answer from the book I used the formula W= Fd; so 400 N * 25.0 m = 1000 J, which is the answer in my book.

Homework Statement a student lifts a book of 0.95 N to a height of 1.25 m. Then the student carries the book to a shelf at a distance of 8.0 m and places it at a height of 2.0 m. How much work did the student realize over the book? Homework Equations W = Fd The Attempt at a Solution...

Yes by the cosine angle, that's the only way I found the tension. It doesn't specify, that's why I'm confused as to what formula to use and when, because the equation gave me the angle so I thought to use the angle but when I did, the book said it wasn't the right answer so then I used to basic...

I'm very confused because the exercises in my book are under the section of using the angle to find work but when I used the basic W= Fd formula I got the answer in the book. How do I know when to use the angle formula to find work and the basic formula?

On my book the answer says it should be 715 N, I divided the Force by the angle & got that answer but everywhere I search it says to use sin & other kinds of formulas I'm confused. Then the second question asks how much work is done if the box is moved 25 m? In my book the answer is supposed to...

Homework Statement Due to friction, a force of 400 N is required to pull a wooden box on the floor. The cord used to pull the box makes an angle of 56° horizontally. How much tension should be on the cord to be able to pull the box? Homework Equations W = Fd * (cosθ) Tension =...

I would have never figured that out. But with this new found information I will try to do it again.

I'm sorry, I'll be more careful.

Then how do I do it?

What do you mean saved? How do I solve it? IDK. The other one made sense to me.

Gah, I'm confused. I'm sorry if it doesn't make sense I'm translating it to English. I'll restate it, this time more carefully. a person uses a cord to pull a boat that has a mass of 100 kg along 50 m by 50 m. along the board walk. The cord makes a 45 degrees angle. If the applied force to the...

the boat is being pulled along the canal by the person towards the board walk. The problem in my book does not say whether the water level is at the same as at the destination so I presume it is.

You're right, I got them mixed up. The real one says, 12000 J of work is required to pull a wagon that weighs 800 N, in a distance of 200 m. If the applied force over the cord is 120 N, what is the angle? Sorry for that.

So; Wweight = 1000 kg * 50 m * cos 45? 35355.3 + Wapp = 40 N * 50 m * cos 45? 1414.2 1414.2 + 35355.2 = 36769.4 J ?:confused:

The question says; a person uses a cord to pull a boat with a mass of 1000 kg by 50.0 m along the board walk. The cord makes a 45 degrees angle with the horizontal force. If a force of 40 N is applied to the boat, how much work is realized?