Recent content by flaxstrax

I am not really interested in researching and all that kind of stuff but i am inspired about business and technology. I have some capital and i have always wanted to make my own company. I am physics/info technology student and i have couple of ideas but i am wondering if any of you knew...

Yeah well that was just a typo, if i had calculated with + there, i would have the answer 12 * pi ,but it was just a typo. Okay ill write the line integral too. But it says -4 pi is correct. r(t)=(2cos t,2 sin t, 2) dr=(-2sin t,2cos t, 0 ) a=(3y,xz,yz^2) I=\int (3y,xz,yz^2)(-2sin t,2cos...

Yeah well that was just a typo, if i had calculated with + there, i would have the answer 12 * pi ,but it was just a typo. Okay ill write the line integral too. But it says -4 pi is correct. r(t)=(2cos t,2 sin t, 2) dr=(-2sin t,2cos t, 0 ) a=(3y,xz,yz^2) I=\int (3y,xz,yz^2)(-2sin t,2cos t, 0...

Is this better? No i don't see where... \int\int (z^2-x,0,z-3)*(x,y,-1) dxdy= \int\int (r^4/4*r*cos t-r^2*(cos t)^2-r^2/2+3)r dt dr= \int\int r^6/4*cos t+r^3*(cos t)^2-r^3/2+3r dt dr= \int r^6/4*sin t-r^3(1/2(t+cos t*sin t)-r^3/2*t+3r*t dr= \int 0-r^3*\pi-0-r^3*\pi+6r\pi dr= \int...

argh i haven't learned how to write equations like you do ... And it takes a second for me to open that link , its HD pic of 1 A4 , like 2,3 mb or something. Ill try and write it then somehow.

http://www.upload.ee/image/3322664/20130520_011715.jpg So please check it out, i think u can understand it better this way :) I don't see where i did wrong, and i can't really understand what you meant by " The only term that should survive the θ integration is part of the cos2θ expression...

I don't understand what you mean ? Sorry, english is not my first language.

Homework Statement I have to control stokes theorem( I have to calculate line-and surface integral. I have a vectorfield a=(3y,xz,yz^2). And surface S is a paraboloid 2z=x^2+y^2. And it is limited by plane z=2. For line integral the line is a circle C: x^2+y^2=4 on the plane z=2. Vector n is...

Did it with spherical coordinates now . Tthis is so impossible :( http://www.upload.ee/image/3302135/20130511_041747.jpg http://www.upload.ee/image/3302136/20130511_041718.jpg

Okay i have 2 solutions. Gauss divergence is correct but the other one is false. In Gauss divergence i took φ bounds incorrectly , its actually 0 to pi/2 , that gives me 2/5 * pi * a^5 . Thats correct answer. But i fail somewhere in direct integrating ... Can someone tell me where i fail...

Homework Statement Find integral I = ∫∫xz^2 dydz + (x^2y − z^3) dzdx + (2xy + y^2z) dxdy (Integrate over A) if A is half a sphere(radius is a). Sphere is given with equation z=(a-x^2-y^2)^1/2 and z=0. Homework Equations The excercise is in 2 parts , find it with just integrating and b)...