Recent content by fonzi

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    Spring mechanics with 2 different masses

    DISREGARD THE LAST POST ITS WRONG. this is a solved problem thanks for the help everyone.
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    Spring mechanics with 2 different masses

    Problem 8 is for the Mass 3m find the time that is required to reach the floor (from the top of the ramp to the floor). I use three formulas v0sin theta =V0y, y = v0yt =1/2 at^2, and the quadratic formula and you solve for t. Problem 9 is Calculate the velocity of the mass 3m at the point of...
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    Spring mechanics with 2 different masses

    thanks tiny tim problem 1 is the same as before for problem two and three we use the formula PE = (mV1^2)/2 + (3mV2^2)/2 to calculate conservation of energy and mv1 =3mv2 to calculate conservation of momentum. this will give you 8.39 m/s for problem 2 and 2.8 m/s for problem three. problem 4...
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    Spring mechanics with 2 different masses

    I'm running out of time can't you just tell me what I need to do? I can do the rest and I have shown an attempt at the problem. Also I know that 1,4,5,and 7 are correct. and their were actually 11 problems and I can solve those If I can find the answer to 2 and 3.
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    Spring mechanics with 2 different masses

    I'm sorry I can't figure this out.
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    Spring mechanics with 2 different masses

    Can you give me a formula or a procedure that I can use, cause I know I'm not doing this right, but I want to know the right way.
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    Spring mechanics with 2 different masses

    OK I'm not quite sure how to do that, But this is my attempt. Because of conservation of momentum I know PE = (.5V1^2)/2 + (1.5V2^2)/2 but that leaves me with two variables, so what do I do? M =.5 and 3M = 1.5, which means I am using the formula KE = (mv^2)/2
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    Spring mechanics with 2 different masses

    why doesn't my answer take into account the conservation of energy and momentum/how do It the right way?
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    Spring mechanics with 2 different masses

    final answers: for problem 1: PE =KE, where PE = potential energy and KE = kinetic energy formula two equals .5K delta X^2. this means PE = (750*.25^2)/2 = 23.44 J for problem 2 I believe you use V = square root (2KE)/m = square root 2(23.44)/.5 = 9.68m/s I believe problem 3 is solved the same...
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    Spring mechanics with 2 different masses

    so T should = .43 because y=.5at^2, so t = square root y/(.5a)
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    Spring mechanics with 2 different masses

    The way I see it I found the x direction velocity in problem 3 so I need to find V that accommodates two dimensions (the x as well as the y). so i am using the formula v0cos 20 = vx so vx/cos20 = v0 which gives me 5.55m/s. So I'm wondering if my method is correct?
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    Spring mechanics with 2 different masses

    I've already solved that, I'm on step 6 but the answer is 22.44, all the info you need is in the first, second, and fourth post.
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    Spring mechanics with 2 different masses

    I'm confused how does that help me find the speed of mass 3m when it leaves the ramp? Your answer seems to be the perspective I need to look at this problem, is their something wrong with how I have been solving the problems? If so where did I mess up and if not using work/energy formulas how do...
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    Spring mechanics with 2 different masses

    I believe I made a mistake on # 5 so what I think I was suppose to do was take the work of the spring - the work of friction = (mv^2)/2 now multiply the new work by 2 divide by m and square root both sides and you get velocity. so the answer should be 9.568 round to 9.57.
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