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In this schematic there is two potential transformers on the left and two current transformers on the right. The potential transformers on the left are connected together by a wire between X2 of the left transformer and X1 of the right transformer. Then there is a wire that must come from one...

That ROCKS!

So the coils here prevent a direct short?

Anyone know where I can find a diagram of how the load completes the 3-phase circuit? On the secondary side, nothing is going to happen until a load draws current right? But how does this complete the loop?

Thanks all for the help. I think I see now what is happening. The three phases are shifted slightly so that there is a smoother power flow into a load. I guess the extra pulses reducing the lull in power between phases as opposed to the spacing between each wave in single phase acts like extra...

Lets consider 3 wire, 3 phase delta.

I'll start from scratch, blank slate. AC 2 phases coming in. How does current move when these two phases are connected?

I'm sorry, I've gotten confused and really goofed up what I'm trying to say. In the picture, we have a wave that is at peak for one phase. It's at 180. The three waves are displaced 120 degrees that's why they are at different heights at any given instant. The one phase is at it's positive...

100V 0 and 100V 120 See, that's not how I thought it was suppose to work. I thought it was like this. One phase is 100V at 120 and another phase is -100V at 120. That makes sense; I see one side as being the positive and the other as being the negative. So initially I thought, yes we can...

oops, yes 120 So when phase 1 is let's say at 120, and it's working in conjunction with a phase that's near zero, how is current able to return?

One hot wire from your meter to the main panel and then a neutral tied to ground only, is that what you mean?

The way I understood it and that made sense when connecting two phases together was that one of the phases was in the exact opposite range(polarity). So one phase would allow current to enter the circuit and then the other phase would allow the current back out of the circuit, back to the...

So then the left half should be reversed in flow? That would then make the neutral have flow in one direction since it can't hold opposite directional flows. But if so, what happens when the two flows hit R5 then?

Ok, so the 120v part of this circuit is going to look somewhat like this right? The neutral is going to carry both opposing phases along it. Does this mean the neutral should always be thicker at this point?

Ok, then considering if a neutral was put in place. How does the power then travel? When it's said that the neutral carries the difference. The difference of amps in the hot legs is flowing through the neutral. What does this mean? So when the current is trying to use the other hot leg as a...