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Components of an Electric field due to a dipole
actually, doing the whole thing from the electric field is ridiculously stupid. I realized I should start it in Volts so it looks like this V = \frac{q}{4\pi\epsilon} (\frac{1}{r-\frac{l}{2}cos\vartheta}-\frac{1}{r+\frac{l}{2}cos\vartheta}) which then simplifies to...- forensics409
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- Forum: Advanced Physics Homework Help
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Components of an Electric field due to a dipole
Ok. but my biggest problem is then simplifying the numerator, and I tried using binomial expansion for that and you get (x^{2}+z^{2}+dz)^{3/2} - (x^{2}+z^{2}-dz)^{3/2} and a denominator of (x^{2} + z^{2})^{3} sorry to ask but what do you do from there?- forensics409
- Post #5
- Forum: Advanced Physics Homework Help
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Components of an Electric field due to a dipole
But how does that help?- forensics409
- Post #3
- Forum: Advanced Physics Homework Help
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Components of an Electric field due to a dipole
Homework Statement The problem is: Show that the components of \vec{E} due to a dipole are given at distant points, by Ex=\frac{1}{4\pi\epsilon{o}} \frac{3pxz}{(x^2+z^2)^{5/2}} and Ez=\frac{1}{4\pi\epsilon{o}} \frac{p(2z^2-x^2)}{(x^2+z^2)^(\frac{5}{2})}}...- forensics409
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- Components Dipole Electric Electric field Field
- Replies: 6
- Forum: Advanced Physics Homework Help
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Components of an Electric field due to a dipole
Homework Statement The problem is: Show that the components of \vec{E} due to a dipole are given at distant points, by Ex=\frac{1}{4\pi\epsilon{o}} \frac{3pxz}{(x^2+z^2)^{5/2}} and Ez=\frac{1}{4\pi\epsilon{o}} \frac{p(2z^2-x^2)}{(x^2+z^2)^(5/2)}}...- forensics409
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- Components Dipole Electric Electric field Field
- Replies: 1
- Forum: Introductory Physics Homework Help