ah yes turns out that is how you do it. using the same method as if it was a point charge, but instead using the potential for an electric dipole.
so the answer comes out looking like:
http://img823.imageshack.us/img823/279/picture006mv.jpg the way i worked it out, that seems right but i...
Homework Statement
[PLAIN]http://img846.imageshack.us/img846/1269/img029z.jpg
2. The attempt at a solution
My attempt and relevant equation is only there in the picture. I know how to find the electric field of an infinite plane np, gaussian pillbox etc.
im not sure what role...
ah yea i thought that looked weird nvm. scratch the two i see my mistake, it was in the subtracting, i basically subtracted the same thing twice and got an extra factor of 2.
the only thing left i did not understand on the test is part e)...
I really appreciate you helping me out with this btw. I've tried many forums/many googles trying to find help on this sort of thing. this is the first place I've gotten real answers i can use.
[PLAIN]http://img44.imageshack.us/img44/1109/picture004so.jpg
thats my second attempt on part...
[PLAIN]http://img815.imageshack.us/img815/7193/picture002sb.jpg
ok this is my last shot
i realized i was doing what i like to call "crazy math", here's my attempt at some 'sane math'.
"A" has to be real idk how to handle the positive part, but here "a" is going to be a negative number so...
i asked my teacher today after class about this part, he showed me a similar way of doing it where he took the wave function and just used the abs(x) so that
http://img213.imageshack.us/img213/504/picture001tq.jpg
if you do it this way, and solve still assuming a<0, then you end up...
for the case where a>0 the integral diverges, for a=0 the whole thing becomes 0, so the only value a can have where A has a finite value (other than 0) is when a<0.
so a is negative.
i tried doing the first one over again with replacing all the a's with (-a)'s but i got the same answer. maybe...
Aha! awesome, thanks.
ok so what I've done from that:
http://img833.imageshack.us/img833/7193/picture002sb.jpg
and doing part b) over i get
[PLAIN][PLAIN]http://img688.imageshack.us/img688/944/picture004ya.jpg
i put a little star next to line 6 cause I am not sure if i did this...
ok I've been really dense, thanks for persisting
hopefully this is what you're talking about:
[PLAIN]http://img545.imageshack.us/img545/7517/picture005x.jpg
do you mean like this
[PLAIN]http://img24.imageshack.us/img24/6184/picture002lpv.jpg
cause then it seems like when you evaluate it, stuff starts going to infinity all over the place.
thats why i broke it into one integral from 0 to +inf and one integral from 0 to -inf. here in these...
Homework Statement
http://img168.imageshack.us/img168/6892/img002pd.jpg
this is the first half of a test we had last friday.
Homework Equations
\phi(k) = \frac{1}{2\pi}\int\Psi(x,0)e^{-ikx}dx
that looks a little funky but i think you understand what I am trying to say.
The...