Recent content by Frankboyle

I added the impedance of the capacitor and inductor, is this not the correct method?

I've re-done my calculations using Zth instead of Zc, does this look better?

So as for the calculations, where I've previously used Zc, should I just use Zth to work out In?

So would this be the correct conversion?

Sorry about the delay, only just had a chance to give part C a go! I'm feeling a bit more sure about this part, but I've attached my work anyway just to be sure

If both sources are suppressed then there wouldn't be any current flowing through the resistor, so it shouldn't affect the Thevenin Impedance

For the Thevenin Impedance, do I need to take into account the resistor from the left side of the circuit? Or just the impedance from the capacitor and inductor?

Ah I understand now! Using -10/7 as the capacitor's impedance I got Vo= 2.6257 + j9.7993

I've re-done my working out for Vo considering that 1/j=-j, am I correct?

Here's my working out for the voltage divider

I used the voltage divider equation to get a value of (70/71)*V for Vo. I then multiplied the cartesian form of V (2.5882 + j9.6593) by 70/71, which gave 2.5517 +j 9.5233 Am I mean't to use (Z1*Z2)/(Z1+Z2) to find ZT, rather than just adding them?

So by using the cartesian form of the voltage, I have gotten to the answer of: VT= 2.5517 + j9.5233 As for ZT, I simply added Z1 and Z2 together to get the overall impedance, which was: ZT=0+j101.429

So here is the circuit when you ignore the current source+resistor. What value do I use for V though? Would I use the peak value of 10V?

So the voltage produced by the current source and resistor in series doesn't affect the voltage produced by the voltage source