Well, PhanthomJay, thank you again for all your timely help - far more than I expected! I've learned a little more.
Most appreciated.
Kind regards, Fred
OK thanks again. So the (horizontal beam) BMD starts off -ve at the cantilever fixing point and continues unchanged to the RHS of the beam; the fixing moment being anticlockwise which balances the clockwise moment at the RHS of beam. This time perhaps?
Yes, I understand 1st and 2nd para results (although I thought since beam would hog with weight the moment at R would be negative by convention). And I'm afraid I can't find any shear force along the beam!
So obviously I still haven't grasped the concept! Thanks for bearing with me on this!
OK thanks. So now the way I see it ...
Horz reaction at Rh = -F
Vert reaction at R can only be due to gravity … something like Rv = -(beam weight*beam length + vertical [baluster] weight) = shear at R
Any closer?
Thanks again for all your help :)
Thanks PhantomJay
But this is where I'm stuck. To me, reaction R = 0 (surely it couldn't be that R = F?), which is counter-intuitive. Another clue perhaps?
Hello
Please see attached - trying to figure shear force and bending moment at reaction point R, with a horizontal force applied at top of Z. This is a veranda deck with balustrade.
If F was vertical, then straightforward with SF = F and M = FX. But when F is horizontal as shown, I'm having...