Recent content by free-node-5

Homework Statement An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.60 mm. 1. If a 25.0 V potential difference is applied to these plates, calculate the electric field between the plates. 2. What is the surface charge density...

*bows head in shame and bumps thread*

nothing you're saying is incredibly unreasonable... but I never tried to convert kj to j ? (I did however have numbers from wiki. that said x kJ/kg which is inherently equal to J/g)

apparently the table on wikipedia was using kJ/kg which threw me off 2.05 J/(gK) *10 K*46g+4.1813 J/(gK) *100K*46g+2.080 J/(gK) *16K*46g + 2260J/g*46g+334J/g*46g = 141031.86 I still don't know if this is right though I also need to know if I was supposed to be adding for the ice to...

Homework Statement How much energy is required to change a 46.0 g ice cube from ice at -10.0°C to steam at 116°C? Homework Equations specific heat c = Q/(m(Tf-Ti)) Q = cm(Tf-Ti) latent heat Q = mL The Attempt at a Solution 2.05*10*46+4.1813*100*46+2.080*16*46 +...

a = 4.76019 T = (m1)(9.8)+(m1)(a) = 29.1204 T = (m2)(9.8*sin59)-(m2)(a) = 29.1204 yay when I started typing this post I was getting inconsistent results but then after poking it a while I figured out that not only did we have m1 and m2 backwards but that I had to add for m1 instead of...

like (m2)(4.76019)=(m2)(9.8)-T ? if so, how did we know to look at the hanging mass as opposed to the one on the slope?

well... all I know is F=ma is that what you mean?

I feel so stupid well then I'd say F=(m2)(9.8)-T oh, so do I set up the one for m1 too and then solve for T? edit: on second thought, that may not make any sense

it's own weight excluding the amount that the other mass, m1 is pulling back on it so... 2

T=(m1+m2)a ?

http://s252.photobucket.com/albums/hh6/invaderjolleyolleyman/?action=view&current=tension1.png Two objects are connected by a light string that passes over a frictionless pulley. The incline is frictionless, m1 = 2.00 kg, m2 = 8.00 kg, and θ = 59.0°. Find the tension in the string...

yeah pretty much that's after some calculations but I used those values for the rest of the questions and they should be accurate

I'm stumped. I was working on a problem in a computerized system that tells you whether you got it right or not and I successfully found everything including the force acting on each end of the string, which in this case is suspended over a (frictionless) pulley. The force on one end is 19.6N...

extreme thanks I'm not sure what I did at this point because I failed so many times but when i fixed that mistake, I managed to get to a correct final solution