Recent content by freeballa

Can anyone else confirm if I did this problem correctly?

It hasn't been simplified, so it isn't in the simplest form. I am just checking if I did the correct steps as I have nothing to compare against to see if the answer is correct. I am not neglecting my homework to do this.

a1x + b1y = r1 and a2x + b2y = r2 X1 = (r1b2-b1r2)/(a1b2-b1a2) Y1 = (a1r2-r1a2)/(a1b2-b1a2) a1x + b1y = r1 and a2x + b2y = s2 X2 = (r1b2-b1s2)/(a1b2-b1a2) Y2 = (a1s2-r1a2)/(a1b2-b1a2) a1x + b1y = s1 and a2x + b2y = r2 X3 = (s1b2-b1r2)/(a1b2-b1a2) Y3 = (a1r2-s1a2)/(a1b2-b1a2)...

Couldn't I just take the determinant of a1, b1, a2, b2? Area = |a1b2 - a2b1|

I think I understand how to do it... Find the intersection of the points: a1x + b1y = r1 and a2x + b2y = r2 a1x + b1y = r1 and a2x + b2y = s2 a1x + b1y = s1 and a2x + b2y = r2 a1x + b1y = s1 and a2x + b2y = s2 Get the (x, y) for each of those points Then subtract two sets by your...

Then the area P would be: P = ||r1 x s1|| or.. P = ||r2 x s2|| Correct?

Homework Statement This isn't really homework, but a not assigned problem out of my mathbook which is kinda confusing me.. #74. We have two pairs of parallel lines in R^2 defined by the linear equations below: a1x + b1y = r1 a1x + b1y = s1 a2x + b2y = r2 a2x + b2y = s2 We assume...