Recent content by frenkie

can roots be at the same points as POI's? because when I set my original equation to zero and I set my second derivative equation to zero i get the same answer? is it possible that roots can be same as the POI's.

thank you very much guys..appreciate your help...

also, are there any interesting points in the graph of sin(x/2)...my last question.

and why is it oscillatory?

I wish i knew what that looks like? is there a picture anywhere? sorry if that's too much trouble.

is y=sin(x) the end behavior of y=sin(x/2)?

is there any interesting points in the graph of sin(x/2)?

oh nvm my PIO is o and positive and negative 2pi? correct?

or pi/2? getting confused all over again.

pi and 2pi which means that x=pi?

I'm not sure how to solve for x when i set my second derivative equal to 0. -1sin(x/2)/4=0 if i do PEMDAS in reverse i get sqrt2/1 multiplied by 4 but i don't think its right

the teacher said that it would be alright if the domain iz [-2Pi, 2Pi] so i think that -Pi and Pi are the x values...which means that -Pi is a min and Pi is a max and 0 is a PIO.? do u agree?

x=Pi? I'm making this way too hard then it actually is.

cos x is zero at Pi/2 and 3pi/2 on the unit circle so when i plug these two numbers into x in my derivative equation i get o for the answer so x is Pi/2 and 3pi/2?

cos(x/2)/2 is my derivative. and when I set it equal to 0, i try to solve for x. so cos(x/2)/2=0 cos(x/2)=0/2 this is the part where I'm stuck...a friend of mine did the rest and he came up with what's on the bottom, but I don't know how he did it or if its right...help? cos x=sqrt2/2