Recent content by fridaycoffee

i found an easier way of solving any kind of convolution thnks anyway for all you help

delta(n-2)+delta(n-3)+delta(n-4)+delta(n-5) ... i don't know how to obtain this answer i made an image with the convolution of [delta[n] + delta[n-2] ] * [delta [n+2] + delta[n+3]] Maybe you can explain better the result on this...

yeah i read it before you post the link :) i mean for example if i have [delta[n] + delta[n-2] ] * [delta [n+2] + delta[n+3]] i continue adding lag until they meet? i misthought about specific lags for non autocorrelation convolution; i just apply the convolution formula

i know what it means :) i thought there are other specific convolutions.. for example what would be the lag for a normal convolution if it follows the same algorithm or it doesnt?

Ok..so for m=-1 the second x[n] = delta[n] + delta[n-1] shifts into delta[n-1] + delta[n-2]. The lag m=-1 is standard for circular convolution ? For m= 1 the answer would be delta[n+1] + 2delta[n] + delta[n-1] but for what would it stand ? I don't have the chance to consult a teacher :(.

1. Oh i got it now :) the first 1 from 011000 was for delta[n+1] but what you mean by 1, 2? one term,2 terms? The possible answers are: a) 2delta[n] + 2delta[n-1] b)delta[n] + 2delta[n-1] + delta[n-2] c)2delta[n-1] + 2delta[n-2] d) delta[n] + delta[n-1] + delta[n-2] e)delta[n-1] -...

1. i meant what 000121000 i terms of δ[n], for zero leg 00022000 = 2δ[n] + 2δ[n-1] ? but 00012100 ? what does "1", "2" , "1" mean in terms of a δ[n] this might be a question at my master degree admision :) 2. Maybe youre right :) , i just applied the formula, and if i do that if |ak| = ( Ak...

1. what does the 000121000 sequence mean ..im not familiarized with this notation..one of the reasons i did not quite understood your answer 2. there are different formulas for the power of the signal a. P = 1/T integral[ Xp (t)2] b. P = Σ|ak|2 c. P = u(t)2 / R The formulas where...

1. if i do that wouldn't it be the sum i stated: δ[n]*δ[n] + δ[n] * δ[n-1] + δ[n-1] * δ[n] + δ[n-1]* δ[n-1] ? and the answer: 2δ[n] + 2δ[n-1]? ..but i have hard time on the result of a multiplication of two diracs or impulses..which term do i keep the first or the second one. 2. maybe but if...

1. so δ[n] would be a stick at n= 0 and δ[n-1] would be a stick at n=1... and next i do the convolution like this ? δ[n]*δ[n] + δ[n] * δ[n-1] + δ[n-1] * δ[n] + δ[n-1]* δ[n-1] = δ[n-1] + δ[n] but its not in the possible results (δ[n] * δ[n-1] beeing = 0; and δ[n] * δ[n] = δ[n], δ[n-1]*...

Homework Statement 1. i need to obtain the result of x[n] * x[n] (convolution) where x[n] = δ[n] + δ[n-1] 2. I need to obtain the power of the signal x(t) = 4 cos (ω0t) + 2 sin (ω0t) + 2cos(4ω0t) for R = 1 k Ω Homework Equations 1.Who do you convolute 2 diracs ? 2. what is the correct...