Recent content by FurFur

oh okay. Yea I'm going to keep practicing since practice makes perfect.

right, since m2 is going down and m1 is going up. It makes perfect sense. Well thank you so much for the help:) and for ur time, it took a while (what a tedious question -_-.. maybe because I am reali slow at physics). By the way, how would I mark that the question has been solved?

oh right! Okay so the equation is: 15.68 - 9.408= 2v^2 + 2.5v^2 6.272= 4.5v^2 6.272/4.5 = v^2 1.39]square root = v 1.18 m/s= v that seems right.

well v1 and v2 must be the same. 15.68 - 9.408= 2 (v1^2' + 1.25v2^2') this still leaves me with 2 unknowns..but both unknowns are equal..hmm

After I've substituted the numbers I get: 15.68 - 9.408= 2v1^2' + 2.5v2^2' im not sure what to do with the right side mathematically

As well, the 2 heights for m1 are : 0m and 0.24m to heights for m2 are : 0m and 0.32m. Im not sure, for both masses, which height is initial and which is fiinal. Both can't start at zero since m1 moves up and m2 moves down.

o okay okay...so to get the final speed of m1 i don't do this: Ek1 +Eg1= Ek2 +Eg2 1/2mv1^2 +mgh1= 1/2mv2^2 +mgh2 1/2(4)(0) + (4)(9.8)(0)= 1/2(4)v2^2 +(4)(9.8)(0.24) 0 +0 = 1/2(4)v2^2 + 9.41 -9.41/0.5(4)= v2^2 -4.71=v2^2 instead for the final speed of m1 i jus leave it at (1/2) 4 v^2...

I edited my post...im not sure what to do about the negetive number

Oh..okay that makes more sense. So the height of mass 1 is 0.24m. Now I need to get the final speed of mass 1. this is what i did: Ek1 +Eg1= Ek2 +Eg2 1/2mv1^2 +mgh1= 1/2mv2^2 +mgh2 1/2(4)(0) + (4)(9.8)(0)= 1/2(4)v2^2 +(4)(9.8)(0.24) 0 +0 = 1/2(4)v2^2 + 9.41 -9.41/0.5(4)= v2^2 -4.71=v2^2 i...

to get the height I am doing 0.40sin53. So when i split the triangle that you've drawn, into 2 the height of both is the same therefore its 0.32.

well the angles are switched. 53degrees is on the left with m2 and 37degrees is on the right with m1

I wish i could upload an image. This is what the triangle looks like. 0.40 is the hypotenuse of the triangle with the angle 53degrees when you split this triangle into two. That is why I am getting 0.32m as my height. Something's wrong...

okay I think I am doing something incredibly wrong in my angles. When i try to get the height of the triangle I am doing 0.40m x sin 53 which gives me 0.32. The height occurs several times in the 8 term equation which is why my answer keeps coming wrong. I am not sure what to do about the height.

oops mistake...for my kinetic energy for m1final I'm getting 12.5 and for the Eg of m1 final I am getting zero

im getting 2.5m/s for my kinetic energy for m1final. For the Eg for m1final I'm getting -12.544. I am not sure if these numbers are right though since in mgh i made g= -9.8.