I understand what you've saying, just that I have yet to reconcile with the fact that even when another path of energy loss is introduced, the total energy loss is always half that of the initial. in the first circuit, radiative loss accounts for all of them. in the second, it's split between...
ok. I guess I'm slightly bothered by this thought:
if you have another circuit that is the same except for the fact that there's a resistor connecting the caps, it's kinda surprising that the energy loss from both circuits are still the same. furthermore, in the resistive circuit, the total...
good answer on the radiative loss. but I'm curious what if there's some resistance in the wire, how do you calculate the loss? I guess I'm puzzled by the fact that without considering the mechanism of energy loss, the calculation shows exactly half of the original energy remains.
does this make sense:
g=gravitational acc
y=water level from base
A=area of water surface
r=water density
m=total mass of water
U=PE
then dU=grAydy
U=1/2grAh^2=1/2mgh (m=rAh)
Suppose you have a cylindrical tank of water that is filled to height h. Total mass of water is M. How do you calculate the potential energy of water relative to the base of the tank?