Recent content by gabe99

The mistake was the missing "-" sign in the left part like @kuruman pointed out, the algebra itself was correct.

That's the feedback that I'd like to receive. This is the approach we were taught. I got it correct now, thank you all for the help.

Could be, no doubt. I just wondered since you said you changed the mass to 100g, and then got the desired result of 39g. The mass of the ice should be around 39 grams. I will check my algebra and come back

Maybe a mistake in the exercise ?

Rounded to 45 grams. The exercise says the answer should be 39 grams

After the equation I tried solving for m_ice

ΔQ_2 + ΔQ_1 = 0. In a closed system the energy is conserved, no energy is lost or gained. -ΔQ_1=ΔQ_2 . The amount of heat/energy lost by the water in this case is equal to the heat gained by the melting of the ice into water, the warming of the water, the warming of the iron. Then I end up...

Would I put a "-" sign before the c_vm_v(-25) ? like -ΔQ_1=ΔQ_2 ? As for the mass of water, should it no be 0.15 kg (since it is 1,5 dl) ?

In my approach, I tried to emulate my equation based on what I learned in the theory of this topic: "Heat is conserved in any such process, consistent with the law of conservation of energy. The amount of heat lost by a warmer object equals the amount of heat gained by a cooler object." In...

The answer should be around 39g. I keep getting around 45g. This is the calculation I tried Any feedback on what I am doing wrong ? Regards!