Recent content by Gadersd

Here is one of my references. http://www.graphics.stanford.edu/courses/cs348b-01/course29.hanrahan.pdf Read the first page.

I am trying to solve the rendering equation with monte carlo integration. I gather all of the incoming radiance from light sources and plug it into the rendering equation. A reference I am using said that radiance does not change with distance. Does this mean that a point light source will...

Should I neglect slide and pitch slip since it it may be difficult to implement? I heard the effects are small.

It seems, from the left graph, that the lift coefficient can be approximated by basic section + elevator angle * constant. How accurate would this be? Also, once I translate my simulation from 2d to 3d, how will I deal with the slide slip? The relation would probably be complex. Would it be...

Also, how accurate is the equation at large angles of attack such as 45 to 90 degrees? I am making a simple plane simulation and I want it to be accurate.

I know that the lift equation for a single wing is L=Cl*0.5*A*r*V^2 where L is lift, Cl is the lift coefficient, A is the area, r is the air density, and V is velocity. Does this equation still apply to the elevator and rudder of a plane or is another equation used? If so, where can I find...

The point on the bottom on the second disk is accelerating faster than the point on the first disk since it is rotating so I must move my hands faster to make up for the greater velocity. Is this correct?

I have never heard of forces having speeds. Never in any of the lessons were speeds of forces mentioned.

Can you use mathematical proof to explain this. I understand claims better when they are in mathematical form.

Yes, the forces are the same, but if I moved my arms faster as DaleSpam suggested then that would output more force which violates my original question.

Wouldn't moving my arms faster output more force?

The second object would not tire my arms any more than the first since the duration and extent of the forces are the same.

The second would not require any more force so it would not be any more difficult to push.

I am having a difficult time wrapping my head around this. If push my hand on the two disks with equal amount of force for 1 second the second one would not be any more difficult to push, yet I am putting more energy into it.

There are two disks of the same size and mass. A 5N force acts through the center of the first and another 5N force acts through the bottom of the other. The forces both point to the right. According to what I have learned, the linear momentum of both objects will be the same, but the second one...