Homework Statement
http://i.imgur.com/5iA1G4i.jpg
A ladder that is 10ft long, weighs 30lbs, and has a 180 lb man standing 5ft up it, resting at 60 degrees on a wallHomework Equations
equilibrium, and torqueThe Attempt at a Solution
180lbs cos60° * 2.5ft + 30lbs cos60° * 10ft = Fwall sin60° *...
alright, thank you. Now the same conversation but a new example, and he still insists that he is correct.
http://i.imgur.com/5iA1G4i.jpg
A ladder that is 10ft long, weighs 30lbs, and has a 180 lb man standing 5ft up it, resting at 60 degrees on a wall. I would approach this problem by first...
I'm sorry, you lost me, it has been a couple of years since I have done none street physics honestly. But it is the cross product of r and F vectors then? Because this other student is saying that you need to use the perpendicular distance (magnitude) instead of r (both a vector sum and not...
http://i.imgur.com/KXYnkqL.png
I drew up the picture in cad so that you can look at it. The find torque would i take the cross product of the length of the beam (10m) and the component of the force that is applied perpendicular to the beam (50Nsin45°)? I then get ≈353.55Nm and then use the...