Recent content by Geoesque

If that is the case then how do I calculate for that?

I thought that when the question asked "Estimate by what percentage g directly above the pocket of oil would differ from the expected value of g for a uniform Earth?" It was asking to find the field directly above the pocket of oil, which is equivalent to 500m below the surface of the Earth due...

The field is suppose to be of the edge of the oil sphere, cause I assumed that the distance from the sphere to Earth is 500m from the Earth's surface. Or should I subtract the 500m from the radius of the Earth since the sphere is beneath the surface?

The units for that are G = 6.67×10-11 N*(m^2/kg^2)

meters per second squared

I don't know why the image link was broken, but I got it here to work. This is what I am visualizing.

https://ton.twitter.com/1.1/ton/data/dm/658364940089032707/658364940126846976/-y9GZJfc.jpg I don't know if I am visualizing this correctly, also how do I find the mass of a spherical shell? Is that what I even have to find for?

center of the sphere of oil is 1km beneath the surface of earth.

The top of a 1km diameter sphere is 0.5km beneath the Earth surface, since the problem states center of the sphere of oil is 1 km.

Homework Statement The center of a 1.00 km diameter spherical pocket of oil is 1.00 km beneath the Earth's surface. Estimate by what percentage g directly above the pocket of oil would differ from the expected value of g for a uniform Earth? Assume the density of oil is 8.0*10^2 (800) kg/m^3...