Recent content by george95

@jbriggs444 , thank you as well!

Thank you once again for the help and answers Jack! This answers my initial post question.

No. So if I assume that the train needs to keep a constant speed of 50 km/h -> 13.89 m/sec both uphill, and downhill - when going downhill an equal amount of energy needs to be consumed in order to prevent the train accelerating beyond 50km/h? If this is so, then regardless of the slope sign...

Thank you Jack, a = F/m means that when train is going downhill, no energy is consumed?

Thank you jack Fs = mg*sin(10) = 50000kg * 9.81 m/s^2 * 0.173648 ~ 86000N P = Fs*v = 86000N * 13.89 m/sec = 1194540 W = 1194 kW So the energy consumption of a train per second when it travels uphill would be 1194kW? Or is this per one meter length of travel, not per second? What about if the...

I am not sure I know how to do that. The "net force" is Fn?

Hi Jack action, According to this video: Fs = coefFriction * Fn coefFriction = tan(10) = 0.176 Fn = mg*cos(10) = 50000kg * 9.81 m/s^2 * 0.9848 ~ 500 000N * 0.9848 ~ 492000N Fs = 0.176 * 492000N ~ 87 000N Is this wrong? Hi jbriggs444. Sorry for the mistake. How do I continue from here?

Why sheet of ice? Because we neglected the friction forces? If we use the length of the ramp to be 1m, then I guess the change should be: sin(10) = altitude/1m altitude = sin(10)*1m = 0.1736*1m = 0.18m Maybe better the change of altitude over one meter of track. Should we increase or...

Hi jbriggs444, I can only assume: mass of the train - 5000kg = 50000N speed = 50 km/h -> 13.89 m/sec inclination of the terrain: 10 degrees (train is climbing up the terrain)But the previous example for work 10 Joules, was if the train was moving horizontally: 10N * 1m = 10 Nm (Joules) Not...

I am not sure I know. Are we now introducing the Power into equation? Work = power * time So if a train has 500 000 Watts (Joules/sec), the work in Joules would be: Work = 500 000 Joules/sec * 1sec = 500 000 Joules ?

1 kg should be approx 10 Newtons (9.81) So the work would be: 10N * 1m = 10 Nm (Jules)?

Thank you for the reply Haruspex, Sorry for the mistakes. Is it possible to simplify the problem by not taking into account friction? So only the energy consumption (not kinetic) while moving under the influence of gravity? Nothing to be honest.

Hi haruspex, I assumed (wrongly) that velocity would be equal: v^2 = acceleration * distance acceleration = gravitAccc * sin(inclinationAngle) And hoped that by knowing it, the energy consumption would maybe be possible to be calculated?

Is there some rule of a thumb formula, which would be able to calculate the energy consumption of a train, based on the following parameters: - mass of the train - its speed - inclination It can be a simple approximation. I would be grateful for any kind of reply.

Thank you once again for the help Rumborak.