Recent content by georgiabrown

I think i corrected my conversion : 60.61 ug/mL = 1.10 * 10^-3 M 1. n = cv = 4.43 *10^-5 2. 1:1 mole ratio 3. final volume = 0.1 L 4. concentration = 4.43*10^-4 is the H3PO4 not involved in the reaction?

Yes, the molarity of permanganate. The concentration on Mn2+ was initially given in ppm (micrograms/mL) and i converted that value to mol/L...

Sorry! The question is to find the final molarity of the solution.

Homework Statement In a lab, 40.3 mL Mn2+ is mixed with 5 mL H3PO4. 0.4g of potassium periodate is added. The flask is heated and then diluted to 100mL. The final solution prepared is a permanganate solution. Calculate the final molarity of the solution. C Mn2+ = 0.06061 M (60.61...