Recent content by ggcheck

I think I figured out the 2nd part: x= y + pi lim[sin(y + pi)/sin(y)] = [sin(y)cos(pi)+cos(y)sin(pi)]/sin(y) = cos(pi) + cot(y)sin(pi) = 1 +0 (x,y)-->(pi,0)

"Which brings up my final question: why did you title this "limits in 3 variables" when your problem has only 2 variables?" I misspoke How about this: Since I have a hunch the limit doesn't exist I prove that it doesn't exist by showing that you get two different limits when evaluating over...

so I'd prove that the original limit doesn't exist by showing: lim[sin(x)/sin(y)] = [sin(pi)/sin(y)] = 0 (x,y)-->(pi,y) lim[sin(x)/sin(y)] = [sin(pi)/sin(0)] DNE (x,y)-->(pi,0)

any tips/ways to approach similar problems?

I'm not really sure what I'm doing... we didn't cover this in class, and the book doesn't have any other similar examples

Homework Statement evaluate the limit or determine that it does not exist. lim [sin(x)/sin(y)] (x,y)--->(pi,0) The Attempt at a Solution since it is not continues at point (pi,0) I can't use use substitution, so I attempted to prove that the limit does not exist by...

3x + ny + 2z = 5 this is it, yes?

3x + 2z = 5 is the solution? It's that simple?

Ax + Cz = 5? cause A and c can be any numbers but D = 5? ugh

uhhh

a point that satisfies 3x + 2z = 5 must also satisfy 0x + 1y + 0z = 0 and some other equation... so we need to find this other equation? how?

I'm still pretty confused

Homework Statement Find all planes in R^3 whose intersection with the xz-plane is the lijne with equation 3x + 2z = 5 The Attempt at a Solution Very confused here, not sure how to start it. the xz plane is another way of saying y = 0... which I'm guessing is why the equation doesn't have a...

time for class--I will review this page later thanks!

ugh how did I get here? I no good with taylor series