the area equation in terms of x is correct, no ? I just want to know if I did my algebra right. I substituted the value of x=\dfrac{3}{2}=\text{1.5 cm} into the area equation and it comes out to \text{3 }cm^{2}. Do you have the same numbers & answer ?
Ray Vickson, I had overlooked this relation! Your relation directly solves w in terms of y avoiding going through using pythagorean theorum and equation 2. Am I right ? or am I right ?
The first relation is the same one I acquired. It is just written differently...
Homework Statement
A rectangle is to be inscribed in a right triangle having sides 3 cm, 4 cm and 5 cm, as shown on the diagram. Find the dimensions of the rectangle with greatest possible area.
Homework Equations
1. x^{2}+y^{2}=w^{2} in terms of w=\sqrt{x^{2}+y^{2}}
2...
if you mean that adding oxygen atoms to C2H5, C4H10 and C6H15 until the correct molar mass is obtained then it either the molar mass is below the required molar mass or too high.
I don't know what 3 possibilities you are referring to. We can't be sure we have a mole of the compound, we not given any information concerning it's mass. If you are talking about something else concerning oxygen then please be more specific.
You could try it yourself. I have attached my paper showing my method. I can send you the file, if it's hard to read on here. If I assume 100 g of the compound, then I can use subtraction to find the mass of oxygen and it turns out to be around 40-41 g
The empirical formula with oxygen is C4H10O13. I don't know how I would add nitrogen since, I don't have the mass of the unknown compound so subtraction from 100% would not work.