Recent content by gibmeanswerz

  1. G

    How do i solve: logx^2 = (logx)^2?

    how about this: 2^y + 5^y-2?? do i subtract?? like: 2^y = -5^y-2 ?
  2. G

    How do i solve: logx^2 = (logx)^2?

    so is it like: logx^2 = (logx)^2 2logx = (logx)(logx) 2 = logx x = 10^2? --> x = b^y = y = b^x ? is that it??
  3. G

    How do i solve: logx^2 = (logx)^2?

    i don't get it...
  4. G

    How do i solve: logx^2 = (logx)^2?

    i do not know how to do this at ALL!
Back
Top