(t+1) dx/dt = x^2 + 1 (t > -1), x(0) = pi/4
I have attempted to work this by placing like terms on either side and then integrating.
1/(x^2 + 1) dx = 1/(t + 1) dt
arctan x = ln |t + 1| + C
x = tan (ln |t + 1|) + C
pi/4 = tan(ln |0 + 1|) + C
pi/4 = C
x = tan (ln |t + 1|)...