Recent content by glpg80

Iron has: 29 electrons 29 protons 30 neutrons the iron ball was charged to +48E-9 C (+48E-9)/(-1.6E-19) = -3E11 Number of Electrons from the Electrical Charge To account for the Electrons in an atom of iron; (1.11E18 atoms)(29 Electrons per atom) = 3.219E19 Electrons total present it as a...

ok, fixed the improper units conversion, kg cancels and mol becomes the correct unit which is then used to calculate the number of atoms, which is 1.11E18

ok, so mass and volume relate to density. i need to find the volume of a 2mm iron ball. V = (4/3)(pi)((0.001m)^3) = 4.19E-9 (7870kg/m^3)(4.19E-9m^3), meters cancel and 3.2976E-5kg = mass how many atoms does it contain? (3.2976E-5 kg)/(0.055845 kg/mol) = 1.84E-6 mol (1.84E-6 mol)(6.022E23...

Homework Statement A 2.0 mm diameter iron ball is charged to +48 nC. What fraction of its electrons have been removed? The density of iron is 7,870 kg/m3. Homework Equations Q = Ne; N = number of atoms in 1 mole, e is atomic charge, Q = point charge N = Avagadro's Constant =...